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www.mikescher.com/www/statics/euler/Euler_Problem-036_explanation.md

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The *trick* here is that we only need to test 1998 numbers. Because there are only so much base10 palindromes:
- The numbers from `1` to `999` mirrored result into to palindromes `11` to `999999`
- The numbers from `1` to `999` mirrored at the last digit result into to palindromes `1` to `99999`
Then we only need to test these numbers whether they are also binary palindromes.