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www.mikescher.com/www/statics/euler/Euler_Problem-071_description.md

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Consider the fraction, `n/d`, where `n` and `d` are positive integers. If `n<d` and `HCF(n,d)=1`,
it is called a reduced proper fraction.
If we list the set of reduced proper fractions for `d <= 8` in ascending order of size, we get:
~~~
1/8, 1/7, 1/6, 1/5, 1/4, 2/7, 1/3, 3/8, 2/5, 3/7, 1/2, 4/7, 3/5, 5/8, 2/3, 5/7, 3/4, 4/5, 5/6, 6/7, 7/8
~~~
It can be seen that `2/5` is the fraction immediately to the left of `3/7`.
By listing the set of reduced proper fractions for `d <= 1,000,000` in ascending order of size,
find the numerator of the fraction immediately to the left of `3/7`.