www.mikescher.com/www/statics/euler/Euler_Problem-036_explanation.md

The trick here is that we only need to test 1998 numbers. Because there are only so much base10 palindromes:

• The numbers from 1 to 999 mirrored result into to palindromes 11 to 999999
• The numbers from 1 to 999 mirrored at the last digit result into to palindromes 1 to 99999

Then we only need to test these numbers whether they are also binary palindromes.